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Problems on finding the area of ​​an arbitrary triangle
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Problem 1: Find the Area Given Two Sides and the Angle Between Them

Problem: The sides of a triangle are 5 and 6 cm. The angle between them is 60 degrees. Find the area of the triangle.

Solution:

To solve this problem, we use the formula for the area of a triangle given two sides and the included angle:

The area of a triangle is equal to half the product of its two sides by the sine of the angle between them

Given:

  • a = 5 cm
  • b = 6 cm
  • γ=60°

Substitute the values into the formula:

S = 1 / 2 × 5 × 6 × sin⁡60°

Using the trigonometric value:

sin⁡ 60° = √3 / 2

So,

S = 1/2 × 5 × 6 × √3 / 2
S = 15 √3/2

Answer: 15√3 / 2


Problem 2: Find the Area of an Equilateral Triangle

Problem: Find the area of an equilateral triangle with a side of 3 cm.

Solution:

The area of an equilateral triangle can be found using the formula:

The area of an equilateral triangle can be found using the formula

Given:

  • a = 3 cm

Substitute the value into the formula:

S=√3 / 4 × 32
S=√3 / 4 × 9
S=9 √3 / 4

Answer: 9√3 / 4 square cm.


Problem 3: Change in Area When Changing the Length of the Sides

Problem: How many times will the area of a triangle increase if the sides are increased by 4 times?

Solution:

Let's assume the original sides of the triangle are a, b, and c. The area of the original triangle can be found using Heron's formula:

Heron's Formula: A representation of the same formula without using the concept of semiperimeter, only through the lengths ofthe sides

If the sides are increased by 4 times, the new sides will be 4a, 4b, and 4c. The area of the new triangle will be:

Решение задачи на соотношение площадей треугольников, если размеры стороны из них увеличены в четыре раза

Answer: The area of the triangle will increase by 16 times.


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 Area of ​​a triangle | Описание курса | Right Triangle